Does the strength of electric field due to an
infinite plane sheet of charge depend upon the distance
of the observation point from the sheet of charge ?
Answers
Answer:
Thus, electric field strength due to an Infinite flat sheet of charge is independent of the distance of the point and is directed normally away from the charge.
Answer:
Electric field intensity produced by single differential charge is given by E = k•dQ/r²R , where dQ is differential charge and R position vector from dQ to any point in the vicinity of point under observation . If we consider infinite charge sheet ( say lying in x-z plane) we can say that there are an infinite number of such differential charge points, total filed is resulted as a result of vector sum of all Electric filed vectors .
.Actually because of symmetry , if we reslove R to x, y, z position vectors, components of Electric field vector of each differential charge add up in such a way that components of electric filed in plane of charge (x-z) at any distance from sheet are are cancelled and the only component that remains is in direction perpendicular to the plain of sheet i.e. say y . Thus along the plane of sheet given there would not be variation in electric filed in x-z plane.
Also, as we move away from sheet i.e along y axis, the effective charge also increases in magnitude , thus cancelling off the effect of increasing distance on y axis. This can be well explained on the basis of Gauss's Law.