Question

does (x-1)(x+2) + 2 have two distinct and real roots​

Answer 1

Step-by-step explanation:

it has two distinct and real roots

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Answer 2

Answer:

yes

Step-by-step explanation:

(x+1)(x-2) + x = 0

x^2 - x + x = 0

x^ - 2 = 0

D = b^2 - 4ac

0 - 4*1*-2

= 8>0