Question

Does x² - 4x + 3√2 have real root​

Answer 1

Step-by-step explanation:

• x² + 4x + 3√2 = 0

--@ROSONI28HERE

Answer 2

Answer:

Yes

Step-by-step explanation:

Here

a = 1, b =-4, c = 3√2

Two distinct real roots, if b²-4ac > 0

Two equal real roots, if b²-4ac = 0

No real roots, if b²-4ac < 0

Here, b²- 4ac

= (- 4)²-4×1×3√2

= 16 - 12√2

Since 16 - 12√2 > 0

Therefore, x² - 4x + 3√2 have 2 distinct real roots.