Question

dog initially running at a speed of 2 metre per second accelerates at a constant rate of 1.5 m per second square for five seconds calculate 1. the distance covered by the dog from its initial position. 2 . rhe final velocity of the dog.

Answer 1

S= Vf^2 - Vi^2 / 2 a
Vf = vi + at
Vf = 2 + 1.5 × 5 = 9.5 m/s
S= (9.5)2 - (2)^2 / 2× 1.5 = 28.75 m

Answer 2

Hi
your answer can be simplified by some formulas :

1.
S=ut + 1/2 at^2
S= 2*5 + 1/2 *1.5*5*5
S = 10 +  18.75
S = 28.75 (distance)

2.
V= u+at
V= 2+ 1.5*5
V= 9.5 ( final velocity)