Domain of f(x)=√x^(2)+x-6/x^(2)-4
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Answer:
Domain is (−∞,−2[∪]3,+∞)
Range is [0,+∞)
Explanation:
Since under square root the polynomial must be positive, the domain is obtained by solving:
x2−x−6≥0
you can obtain the zeroes of the polynomial by solving the associated equation:
x2−x−6=0
x=1±√1−4⋅(−6)2
x=1+√252
x=1±52
x=−2andx=3
so the disequation is solved in the external intervals:
x<−2andx>3
the the domain is:
(−∞,−2[∪]3,+∞)
Since f(x) is positive, due to the result of square root, the range includes all positive real numbers: x≥0
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