Question

domain of function f(x) = root16+x^2

Answer 1

Step-by-step explanation:

$f(x) = \sqrt{16 + {x}^{2} }$

The value under the square root cannot be negative.

x² have all the values of all positive real numbers.

So X² cannot be negative.

so 16 + x² cannot be negative for any real number.

So the domain of the function is all real numbers

$( - \infty \: \: \infty )$