Question

Domain of function G(t) = 2/ t^2-16

Answer 1

Given :

$\sf \large G(t) = \dfrac{2}{ {t}^{2} - 16}$

To find :

• Domain of the given function

Solution :

We have to find domain of given function :-

$\sf \implies G(t) = \dfrac{2}{ {t}^{2} - 16}$

We know that , denominator cannot be zero.

$\sf \therefore{ {t}^{2} - 16} \ne0$

$\sf \implies{ {t}^{2} } \ne 16$

$\sf \implies{ {t} } \ne \sqrt{16}$

$\sf \implies{ {t} } \ne \pm4$

This means that , t ≠ 4 and t ≠ -4

$\sf\therefore \: t \in R - \{ \pm 4 \}$

So, domain of the given function can be any real number except +4 or -4.

Answer :

$\therefore \sf domain : \\ \sf\large \: t \in R - \{ \pm 4 \}$