domain of
function Sin (log x^2/2)
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Problem: Find domain of sin−1[log2(x2)]
Solution: log2(x2) is defined for x2>0
log2(x2) is defined for x>0
Also domain of sin−1x is [−1,1]
When x=1 ,then log2(x2) becomes −1
When x=4 ,then log2(x2) becomes 1
So domain is [1,4]
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