Question

domain of the function f(x)=
$\frac{1}{x + 5}$
is
​

Answer 1

Answer:

The domain is  R-(5)

Step-by-step explanation:

y=1/x-5

y(x-5)=1

yx-5y = 1

yx=1+5y

x=1+5y/y

f^-1(x)= 1+5x/x

therefore the domain of f^-1(x) is d      = R - (0)

                                                        f^-1

i dint know how to write the last part so i wrote it like that

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