domain of the function f(x)= (x²-1)½
Answers
Answered by
2
F(x)=√(x²-1) +1/√(x²-3x+2)
Since the domain of any function must be in the set of Real numbers.
Sox²-1≥0 and x²-3x+2>0(x+1)(x-1)≥0
and x²-x-2x+2≥0(x-(-1))(x-1)≥0 and
x(x-1)-2(x-1)≥0(x-(-1))(x-1)≥0 Π (x-1)(x-2)≥0x€
{(-oc,-1]U[1,oc) Π(-oc,1]U[2,oc)x€(-oc,-1]U[2,oc)
Similar questions