Math, asked by randomness911, 2 months ago

domain of the function f(x)= (x²-1)½​

Answers

Answered by Anonymous
2

F(x)=√(x²-1) +1/√(x²-3x+2)

Since the domain of any function must be in the set of Real numbers.

Sox²-1≥0 and x²-3x+2>0(x+1)(x-1)≥0

and x²-x-2x+2≥0(x-(-1))(x-1)≥0 and

x(x-1)-2(x-1)≥0(x-(-1))(x-1)≥0 Π (x-1)(x-2)≥0x€

{(-oc,-1]U[1,oc) Π(-oc,1]U[2,oc)x€(-oc,-1]U[2,oc)

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