Question

Domain of the function Sin3x/Cos2x

Answer 1

Step-by-step explanation:

Given sin3x=cos2x

⟹cos(

2

π

−3x)=cos2x

⟹

2

π

−3x=2nπ±2x,n∈Z

⟹

2

π

−3x=2nπ+2x or 2

π

−3x=2nπ−2x

⟹x=

10

π

−

5

2nπ

or x=

2

π

−2nπ

In the interval ( 2π ,π) ,x=

1

09π

So number of solutions is 1