domestic lighting circuit has a fuse of 5 ampere if the mains supply is at 230 volts calculate the maximum number of 36 watt tube lights that can be safely used in this circuit
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Let the maximum number of tube-lights be y.
Power of y tube-lights, P=36y
V=230V, I=5A
We know that
P = VI 36y = 230 x 5
36y = 1500
y=31.94
So, number of tube-lights required are 31
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Power of y tube-lights, P=36y
V=230V, I=5A
We know that
P = VI 36y = 230 x 5
36y = 1500
y=31.94
So, number of tube-lights required are 31
please follow me and mark me as brainliest if my answer has helped you
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