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Date
a
(sin B- sinc ) + b(sin C- Sin A
c(sinA- SinB) =0
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Answer:
A(sinB-sinC)+b(sinC-sinA)+c(sinA - sinB) = 0
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sin A/a = sin B/b = sin C/c = k ........... sine rule triangle
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LHS = a(sinB-sinC)+b(sinC-sinA)+c(sinA - sinB)
= a (kb - ck)+b (ck - ak)+c (ak - bk)
= k[ab - ac + bc - ab + c a - bc]
= k[0]
= 0
= RHS
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