Math, asked by bhayyusahu171, 11 months ago

don't answer if not know the solution ​

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Answered by parthbhangale1
0

answer is y8 is answer this question

Answered by amitsnh
1

x + iy = (a + ib)^2

= a^2 + (ib)^2 + 2ab i

= a^2 + i^2b^2 + 2ab i

= a^2 - b^2 + 2ab i

on comparing real and imaginary part

x = a^2 - b^2

y = 2ab

now

x^2 + y^2 = (a^2 - b^2)^2 + (2ab)^2

= (a^2 - b^2)^2 + 4a^2b^2

= (a^2 + b^2)^2

(using identity (a+b)^2 = (a-b)^2 + 4ab)

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