DON'T ANSWER IRRELEVANT OR DON'T SPAM!!
prove this one:-
Answers
Answered by
0
cos θ + sin θ = √2 cos θ
sin θ = √2 cos θ - cos θ
sin θ = ( √2 - 1 ) cos θ
= [ sin θ / ( √2 - 1 ) ] = cos θ
= [ sin θ ( √2 + 1 ) / ( 2 - 1 ) ] = cos θ
We rationalized the denominator in the 2nd step
=> [ √2 sin θ + sin θ ] = cos θ
=> cos θ - sin θ = √2 sin θ
Answered by
1
Answer:
see image for answer
good night
Attachments:
Similar questions