Math, asked by Anonymous, 2 months ago

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Answered by MissCardiologist
1

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a) 97^2 = (90+7)^2 = 90^2 + 2×90×7 + 7^2 = 8100 + 1260 + 49 = 9409.

Note :- 1st question was solved using identity:- (a+b)^2 = a^2 + 2ab + b^2

b) Using the identity (x+a)(x+b) = x2+(a+b)x+ab

Writing 102 as 100+2 and 98 as 100−2

Hence (100+2)(100−2) = 1002+[2+(−2)]100+(2)(−2)

= 10000+(0)100−4

= 9996

The answer is 9996

Answered by mannanreema41
2

Answer:

(a) 97²

(100 - 3)²

(a - b)² = a²+b²-2ab

(100 - 3)² = (100)²+(3)²-2×100×3

= 10000+9-600

= 10009-600

= 9409

(b) 101×98

(100+1) × (100-2)

(x+a) (x+b) = x²+(a+b)x+ab

= (100)²+(1-2)100+1×-2

= 10000-100-2

= 10000-102

= 9898

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