Don't Copy Paste
The work function of the following metals is given : Na 2.75 ev, K = 2.3 eV, Mo =
4.17 eV and Ni = 5.15 eV. Which of these metals will not cause photoelectric
emission for radiation of wavelength 3300 Å from a laser source placed 1 m away
from these metals? What happens if the laser source is brought nearer and placed
50 cm away?
Answers
Answered by
3
hi love my life
its ur answerE=hcλE=hcλ=6.63×10−34×3×1083300×10−10×(1.6×10−19)=6.63×10−34×3×1083300×10−10×(1.6×10−19)=3.75ev=3.75evIt is clear that this energy of the incident radiation is greater than the work function of NaNa and kk but less than that of M0M0 and NiNiEmission will occur in Na and k
its ur answerE=hcλE=hcλ=6.63×10−34×3×1083300×10−10×(1.6×10−19)=6.63×10−34×3×1083300×10−10×(1.6×10−19)=3.75ev=3.75evIt is clear that this energy of the incident radiation is greater than the work function of NaNa and kk but less than that of M0M0 and NiNiEmission will occur in Na and k
zebronics:
mark me as a brainliest
Similar questions