Math, asked by emelycansing, 4 months ago

don't delete please I need answers passed on Wednesday::
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Directions: perform the indicated operation in the expression. ​

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Answers

Answered by spiderman2019
2

Answer:

Step-by-step explanation:

5x/x+2  + - 3/x-3 - 2x/x-3

=> 5x/x+2 - 2x+3/ x - 3

//Take LCM

=> 5x(x-3) - (2x+3)(x+2) / (x+2)(x-3)

=> 5x² - 15x -3x - 6 -2x² - 4x / (x+2)(x-3)

=> 3x² - 22x - 6/  (x+2)(x-3)

=>3x² - 22x - 6/x² -x - 6

Answered by Anonymous
5

  \frac{3 {x}^{2} - 22x - 6 }{{x}^2-x-6}

Solution :

 =  \frac{5x}{x + 2}  +  \frac{ - 3}{x - 3}  -  \frac{2x}{x - 3}

 =  \frac{5x}{(x + 2)}  +  \frac{ - 3 - 2x}{(x - 3)}

 =  \frac{5x}{(x + 2)}    -   \frac{2x + 3}{(x - 3)}

Now Let's Take LCM,

 =  \frac{5x(x - 3) - (2x + 3)(x+2)}{(x + 2)(x - 3)}

 =  \frac{5 {x}^{2} - 15x - 2{x}^{2} - 4x-3x-6 }{(x - 2)(x - 3)}

 =  \frac{5 {x}^{2} - 2{x}^{2} -15x-4x-3x- 6 }{{x}^{2}-3x+2x-6}

 =  \frac{3 {x}^{2} - 22x - 6 }{{x}^2-x-6}

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