Question

don't give direct ans... it's a request... plz give Ans only in full ​

Answer 1

Step-by-step explanation:

-(x+y) = (-x) + (-y)

(i) x = 3/4 , y = 6/7

put the values in above equation

-(3/4 + 6/7) = (-3/4) + (-6/7)

take LCM on L.H.S to add the numbers

$- ( \frac{21 + 24}{28} ) = - \frac{3}{4} - \frac{6}{7}$

taking LCM on R.H.S to solve fraction

$\frac{ - 45}{28} = \frac{ -21 - 24 }{28}$

-45/28 = -45/28

LHS = RHS

verified

Answer 2

Your Answer:-

(i) x = 3/4 and y = 6/7

First solving LHS

-(x+y)

$\tt = -(\dfrac{3}{4}+\dfrac{6}{7}) \\\\ \tt = - [\dfrac{(3\times7) +(6\times4)}{28}] \\\\ \tt =-[\dfrac{21+24}{28}] \\\\ \tt = -[\dfrac{45}{28}] \\\\ \tt =-\dfrac{45}{28}$

Now solving RHS

$\tt (-x)+(-y) \\\\ \tt =(-\dfrac{3}{4})+(-\dfrac{6}{7}) \\\\ \tt = -\dfrac{3}{4}-\dfrac{6}{7} \\\\ \tt =\dfrac{-21-25}{28} \\\\ \tt = \dfrac{-45}{28}$

So, LHS = RHS

verified

(ii) x = -3/4 and y = -6/7

First Solving LHS

-(x + y)

$\tt = -(\dfrac{-3}{4}+\dfrac{-6}{7}) \\\\ \tt = - [\dfrac{-(3\times7) -(6\times4)}{28}] \\\\ \tt =-[\dfrac{-21-24}{28}] \\\\ \tt = -[\dfrac{-45}{28}] \\\\ \tt =\dfrac{45}{28}$

Now Solving RHS

$\tt (-x)+(-y) \\\\ \tt =-[(-\dfrac{3}{4})]+[-(-\dfrac{6}{7})] \\\\ \tt = \dfrac{3}{4}+\dfrac{6}{7} \\\\ \tt =\dfrac{21+25}{28} \\\\ \tt = \dfrac{45}{28}$

So, LHS=RHS

verified

In both the cases LHS=RHS