Question

don't joks please.. give me a full answer .

the sum of a two - digits number and the number obtained by interchanging the digits is 143.If the digits at the units place is 3 more than the digits at the tens place, find the original number. ​

Answer 1

Answer:

58 is the original number.

Step by step explanation:

Given:

• Sum of the 2-digit number and the number obtained by interchanging the digits is 143. ...( 1 )
• Unit digit is 3 more than the tens digit. ...(2)

To Find:

• The Original number.

Let the tens digit = x

Let the unit digit = y

The number becomes 10x + y

After interchanging the digits, the number becomes 10y + x

From ( 2 )

y = 3 + x ...(3)

From ( 1 ):

⟹ 10x + y + 10y + x = 143

⟹ ( 10 + 1 )x + (10 + 1 )y = 143

⟹ 11x + 11y = 143

⟹ 11 ( x + y ) = 143

⟹ x + y = 143/11

⟹ x + y = 13

From (3),

⟹ x + (3 + x ) = 13

⟹ 2x + 3 = 13

⟹ 2x = 13 - 3

⟹ 2x = 10

⟹ x = 10/2

⟹ x = 5

Tens digit = x = 5

Unit digit = (x + 3) = (5 + 3) = 8

The original number = xy = 58

Verification:

The number + number obtained by reversing the digit should be 143

The number = 58

Number obtained by reversing = 85

⟹ 58 + 85 = 143

hence verified .