Question

don't post irrelevant answers

Answer 1

Answer:

Step-by-step explanation:

㏒  $(2x + 1) = 1 - log(x - 1)$

x must be greater than 1

$log(2x + 1) + log(x - 1) = 1$

$log[(2x + 1)(x - 1)] = 1$

$log(2x^2 - x - 1) = log(10)$

$2x^2 - x - 1 = 10$

$2x^2- x - 11 = 0$

The solution to the quadratic equation that is greater than 1

is also the solution to the original logarithmic equation:

$x = [-b + \sqrt{x} (b^2- 4ac)]/2a$

$x = (1 + \sqrt{x} 89)/4$

hope it helps

:)

Answer 2

Answer:

kaisi hai Babu❤

Step-by-step explanation:

................