Question

don't put silly amswers please​

Answer 1

Answer:

Let theta = x

as x belongs to (- pie, 0)

so x/2 belongs to ( - pie/2, 0)

x/2 lies in 4th quadrant.

Consider

${tan}^{ - 1} \sqrt{ \frac{1 - cosx}{1 + cosx} } \\ = {tan}^{ -1 } \sqrt{ \frac{2 {sin}^{2} \frac{x}{2} }{2 {cos}^{2} \frac{x}{2} } } \\ = {tan}^{ - 1} |tan \frac{x}{2} | \\ = {tan}^{ - 1} ( - tan \frac{x}{2} ) \\ = - \frac{x}{2}$

Answer 2

Answer:

I don't know answer but one is enough right?? my brother said it always his answers are correct