Question

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Answer 1

ANSWER

⋆

∫e^x(tanx+1)secx

=∫e^x(secx.tanx + secx)

it is of form

∫e^x(f(x) + f'(x))

=e^x.f(x) + C

here, f(x) = secx

hence,

I = e^x.f(x) + C

= e^xsecx + C

Answer 2

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