Question

Don't spam ..............​

Answer 1

$\huge\mathtt\pink{Solution}$

AB = DC ‎ ‎ ‎‎ ‎‎ ‎ ‎ ‎ ‎‎‎‎ ‎ ‎ ‎ ‎‎‎‎ ‎- - - - (1)

& ∠DAB = ∠CBA ‎ ‎‎ ‎‎ ‎ ‎ ‎- - - - - (2)

${\sf{\underline{\underline{\pink{To \ prove}}}}}$

1. △ABD ≅ △BAC
2. BO = AC
3. ∠BAD = ∠BAC

${\sf{\underline{\underline{\pink{proof}}}}}$

$\sf\pink{1)}$In △ABD & △BAC

AD = BC (Given)

∠DAB = ∠CBA (Given)

AB = AB(common)

△ABD ≅ △BAC ( By SAS rule)

$\sf\pink{2)}$⛬ BD = AC ( CPCT)

$\sf\pink{3)}$∠ABD = ∠BAC (CPCT)