Question

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Answer 1

Answer:

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Step-by-step explanation:

For the numbers (a+b) & (c+d),AM≥GM

⇒2(a+b)+(c+d)≥(a+b)(c+d)

⇒ M≤1 ⇒ M≤1

∵(a+b) and (c+d) are positive, M>0

Answer 2

Step-by-step explanation:

let,

a+b=1. c+d=1

a+b+c+d=2

M= (a+b)(c+d)

= 1×1

= 1

...666....