Question

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Answer 1

Answer:

Given: A car starts from rest and moves along the x-axis with a constant acceleration of 5 m/s2 for 8 seconds

To find: what distance will the car cover in 12 seconds since it started from rest

Solution:

We know that,

s= ut + 1)2 at²

But given that, the initial velocity is zero. Therefore, the distance covered by the car in first 8 seconds is

=> s= 0+1/2×5×8²

=> s= 160 meters

Therefore, the velocity attained at the end of 8 seconds is:

from, v=u + at

=> v = 0+5×8=40m/s

Therefore, since the car has moved with constant velocity from 8th second to 12 second, the distance traveled is

s= v × t = 40 × 4 =160 m

Therefore, the total distance traveled is

160 + 160 = 320 m

Answer 2

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:

Given: A car starts from rest and moves along the x-axis with a constant acceleration of 5 m/s2 for 8 seconds

To find: what distance will the car cover in 12 seconds since it started from rest

Solution:

We know that,

s= ut + 1)2 at²

But given that, the initial velocity is zero. Therefore, the distance covered by the car in first 8 seconds is

=> s= 0+1/2×5×8²

=> s= 160 meters

Therefore, the velocity attained at the end of 8 seconds is:

from, v=u + at

=> v = 0+5×8=40m/s

Therefore, since the car has moved with constant velocity from 8th second to 12 second, the distance traveled is

s= v × t = 40 × 4 =160 m

• Therefore, the total distance traveled is 160 + 160 = 320 m