Question

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Answer 1

Answer:

A point on the axis of a bar-magnet and

@ A point on the equatorial line of the bar-magnet. Compare the magnetic fields in

the two cases, if these points be equidistant from the centre of the magnet and the

magnet be a short one.

What do you mean by magnetic potential at a point? Obtain an expression for the mag-

netic potential, at any point on the axial line of a magnet.

Derive an expression for the torque on a magnetic dipole placed in uniform magnetic

field. Hence define magnetic dipole moment.

state and explain tangent law when a magnetic needle, free to rotate in a horizontal plane

is placed in crossed fields at right angles to each other.

What are the elements of earth's magnetic field? Explain their meanings. Show these

elements in a labeled diagram and deduce various relations between them.

1. Define the terms geographic axis, magnetic axis, magnetic equator, magnetic meridian

and geographic meridian

2 What is terrestrial magnetism? What are the causes of terrestrial magnetism.

3. What is the force between two magnetic poles of strength 3.2 Am and 3.6 Am at a

distance of 12 cm from one another?

(Ans : 9.6 × 10-N)

4 Abar-magnets of magnetic moment 5.0 Am has poles 20 cm apart. Find the pole strength.

[Ans : 25 Am]

Answer 2

${\sf{\underline{\underline{\pink{Solution:-}}}}}$

Construct a line m and n from A and B intersect at P.

$\sf\green{So \ we \ get}$

• OB ⊥ m and OC n

• So m ⊥ n

$\sf\pink{We \ can \ also \ write \ it \ as}$

• OB ⊥ OC

Since APB is a right angle triangle

$\sf\red{We \ know \ that}$

• ∠APB = 90°

$\sf\purple{So \ we \ can \ write \ it \ as}$

• ∠APB = ∠PAB + ∠PBA

$\sf\orange{By \ substituting \ the \ values}$

• 90° = ∠2 + ∠3

We know that angle of incidence is equal to the angle of reflection

$\sf\pink{So \ we \ get}$

• ∠1 = ∠2 and ∠4 = ∠3

$\sf\orange{It \ can \ be \ written \ as}$

• ∠1 + ∠4 = ∠2 + ∠3 = 90°

$\sf\purple{We \ can \ write \ it \ as}$

∠1 + ∠2 + ∠3 + ∠4 = 180°

$\sf\orange{ We \ know \ that}$ ∠1 + ∠2 = ∠CAB and ∠3 + ∠4 = ∠ABD

∠CAB + ∠ABD = 180°

According to the diagram ∠CAB and ∠ABD are consecutive interior angles when the transversal AB cuts BD and CA.

Therefore, it is proved that CA || BD.