Don't spam help me with the trick and explanation. 1 point bonus.
Need trick as early as possible.
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any number divide by 4 , and gives remainder three ,
will be in form
4x+3 , where x is more than 1 .
so, our first number will be
4*2+3 = 11 ,
second number ,
4*3+3 = 15
so, on
Now,
near to 300 , last number that satisfy the above condition will be = 299
so, our series is =
11 , 15 , 19, ______________, 299
Tn = a + (n-1)d
299 = 11 + (n-1)4
299-11+4 = 4n
4n = 292
n = 73 (Ans)
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