Question

#don't spam here... ,​

Answer 1

${\huge{ \large{ \boxed{ \boxed{ \underline{ \sf{ \purple{ \star{Answer{ \star}}}}}}}}}}$

$\boxed{ \green{\bf{Angle\:of\:Reflection = 30^{\circ}}}}$

Angle between the normal and the incident ray = 30°

Explanation:-

• Let AO be the incident ray, Let OB be the reflected ray and Let M, M ' be the plane mirror..

Let us name the parts of the mirror

• AO = Incident Ray

• OB = Reflected Ray

• M, M' = Mirror

♤ To Find ♤

• Angle of Reflection

• Angle between the normal and incident ray

♧ SolutioN ♧

Firstly Let us find the angle between the normal and incident ray. We know that normal is perpendicular to the mirror. So, Normal = 90°.

Given that the glance angle of incidence[I.e the Angle between the incident ray and the normal] = 60°[ I.e Angle Between The Mirror And The Incident ray]

So, Angle of Incidence = 90° - 60°

Angle of Incidence = 30° .

• So, according to the Laws of Reflection

• Angle of Incidence = Angle of Reflection

• Angle of Incidence = 30°

So, $\boxed{ \green{\bf{Angle\:of\:Reflection = 30^{\circ}}}}$

So, angle between the incident ray and the Normal [I.e The Angle of Incidence] = 30°

Answer 2

Step-by-step explanation:

Let AO be the incident ray, Let OB be the reflected ray and Let M, M ' be the plane mirror..

Let us name the parts of the mirror

AO = Incident Ray

OB = Reflected Ray

M, M' = Mirror

♤ To Find ♤

Angle of Reflection

Angle between the normal and incident ray

♧ SolutioN ♧

Firstly Let us find the angle between the normal and incident ray. We know that normal is perpendicular to the mirror. So, Normal = 90°.

Given that the glance angle of incidence[I.e the Angle between the incident ray and the normal] = 60°[ I.e Angle Between The Mirror And The Incident ray]

So, Angle of Incidence = 90° - 60°

Angle of Incidence = 30° .

So, according to the Laws of Reflection

Angle of Incidence = Angle of Reflection

Angle of Incidence = 30°