Question

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Answer 1

Explanation:

after 2 seconds,velocity will be 4+2+4=10m/s

s=v×t

=10×2

=20m

a=(v-u)/t

=(10-0)/2

which is 5m/s

Answer 2

Answer:

We know, ds/dt = velocity

Hence integration of velocity gives displacement.

So, integration of t² + t + 4 will give displacement

$\int\limits^2_0 ({t^{2} + t + 4 }) \, dx$

 $= [\frac{t^{3}}{3} + \frac{t^{2} }{2} + 4t]^2_0$

= 41/3 m

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