Question

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Answer 1

There are 6.022\times 10^{21}6.022×10

21

molecules of water.

Mass of water drop =0.18 g

Molar mass of water=,18 g/mol

Mole of water in a drop:

\frac{0.18 g}{18 g/mol}=0.01 mol

18g/mol

0.18g

=0.01mol

Number of water molecules in 0.18 g of water drop:

0.01 mol\times 6.022\time 10^{23} molecules=6.022\times 10^{21} molecules0.01mol×6.022\time10

23

molecules=6.022×10

21

molecules

6.022\times 10^{21}6.022×10

21 is the answer

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