Question

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Answer 1

Explanation:

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Given :-

Mass of AgNo3 = 3.4 gram

Mass of NaCI = 1.5 gram

Mass of AgCI = 2.8 gram

To Find :-

Mass of NaNo3

Solution :-

By using the law of conservation of mass

AgNo3 + NaCI = AgCI + NaNo3

3.4 + 1.5 = 2.8 + NaNo3

(3.4 + 1.5) - 2.8 = NaNo3

4.9 - 2.8 = NaNo3

2.1 = NaNo3

Mass of NaNo3 is 2.1 grams

_______________________

Answer 2

Answer:

Reaction:

NaCl+AgNO

3

→AgCl+NaNO

3

1 mole of sodium chloride reacts with 1 mole of silver nitrate to form 1 mole of silver chloride and one mole of silver nitrate.

58.5 g of sodium chloride reacts with 170 g of silver nitrate to form 143.5 g of silver chloride and 85 g of sodium nitrate.

Explanation:

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