Question

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Answer 1

Answer:

(b) is the right answer

Explanation:

let u be the initial velocity.

∴ initial kinetic energy is K = (1/2)mu²

at the maximum height velocity is u cos60 = (u/2)

∴ kinetic energy at the maximum height is KE=(1/2)m(u/2)²

                                                                        =(1/4)k

=k/4 Answer

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Answer 2

Explanation:

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