Question

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Answer 1

$\huge \color{red}answers$

1) 7x-3y = 32

firstly put value of x is 3 and y is -3

=> 7(3)-3(-3)

=> 21+9

=> 30 ≠ 32

so (3,-3) does not satisfies the equation..

now..put value of x is 4 and y is -1

=> 7(4)-3(-1)

=> 28+3

=> 31 ≠ 32

so (4,-1) does not satisfies the equation..

now put value of x is 4 and y is 1

=> 7(4)-3(1)

=> 28-3

=> 25 ≠ 32

so (4,1) doesn't satisfies the equation..

now put the value of x is 3 and y is 3

=> 7(3)-3(3)

=> 21-9

=> 12 ≠ 32

so (3,3) does not satisfies the equation..

answer 1 :- hence, there is a mistake in question or in options...none of these is right answer..☺️☺️

2) option b 2 variable

3) option a power of equation is 1 1

4) option d in fourth quadrant (+,-)

5) 2x+y = 5 and 2y = 6

put the value of x is 1 and y is 3 (1,3)

=> 2(1)+3 =5 and 2(3) = 6

=> 5=5 and 6=6

since LHS = RHS

so..(1,3) is a solution of equations..

hence..

option a is the right answer...

6) option c. 16 sets is the right answer..

7) option a {1,3} is the right answer..

8) option a {3,4} is the right answer

9) option b George Cantor is father of set

10) option d {1,2,3,4} is the right answer..

☺️✌️

Answer 2

Step-by-step explanation:

$</p><p></p><p>\huge\pink{\fbox{\tt{࿐αɴѕωєя࿐}}} </p><p> </p><p>$$</p><p></p><p>\huge\pink{\fbox{\tt{࿐αɴѕωєя࿐}}} </p><p> </p><p>$

$</p><p> </p><p></p><p>\begin{gathered}\dashrightarrow\sf\:\:(Diagonal)^2=(Length)^2+(Breadth)^2\\\\\\\dashrightarrow\sf\:\:(BD)^2=(BC)^2+(CD)^2\\\\\\\dashrightarrow\sf\:\:(BD)^2=(24\:cm)^2+(7\:cm)^2\\\\\\\dashrightarrow\sf\:\:(BD)^2=576\:cm^2+49\:cm^2\\\\\\\dashrightarrow\sf\:\:(BD)^2=625\:cm^2\\\\\\\dashrightarrow\sf\:\:BD=\sqrt{625\:cm^2}\\\\\\\dashrightarrow\sf\:\:BD=\sqrt{25\:cm \times 25\:cm}\\\\\\\dashrightarrow\:\:\underline{\boxed{\sf BD=25\:cm}}\qquad\bigg\lgroup\bf Diagonal\bigg\rgroup\end{gathered} </p><p>⇢(Diagonal) </p><p>2</p><p> =(Length) </p><p>2</p><p> +(Breadth) </p><p>2</p><p> </p><p>⇢(BD) </p><p>2</p><p> =(BC) </p><p>2</p><p> +(CD) </p><p>2</p><p> </p><p>⇢(BD) </p><p>2</p><p> =(24cm) </p><p>2</p><p> +(7cm) </p><p>2</p><p> </p><p>⇢(BD) </p><p>2</p><p> =576cm </p><p>2</p><p> +49cm </p><p>2</p><p> </p><p>⇢(BD) </p><p>2</p><p> =625cm </p><p>2</p><p> </p><p>⇢BD= </p><p>625cm </p><p>2</p><p> </p><p> </p><p> </p><p>⇢BD= </p><p>25cm×25cm</p><p> </p><p> </p><p>⇢ </p><p>BD=25cm</p><p> </p><p> </p><p> </p><p> </p><p>⎩</p><p>⎪</p><p>⎪</p><p>⎪</p><p>⎧</p><p> </p><p> Diagonal </p><p>⎭</p><p>⎪</p><p>⎪</p><p>⎪</p><p>⎫</p><p> </p><p> </p><p> </p><p> </p><p></p><p>⠀</p><p></p><p>\therefore\:\underline{\textsf{Hence, Length of Diagonal is C) \textbf{25 cm}}}.∴ </p><p>Hence, Length of Diagonal is C) 25 cm</p><p> </p><p> .$