Question

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polynomials question:
FIND p(0),p(-1) and p(2) for the following case:- p(x)=(x-1) (x+1)​

Answer 1

Answer:

(0) square (-1)

0(-1)

0

p(-1)= (-1) square (-1)

1-1

0

p(2)= (2) square (-1)

4-1

3

Step-by-step explanation:

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Answer 2

p (0)= (0-1)(0+1)

= -1×1

= -1

p (-1)=(-1-1)(-1+1)

= -2×0

=0

p (2)=(2-1)(2+1)

= 1×3

= 3

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