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polynomials question:
FIND p(0),p(-1) and p(2) for the following case:- p(x)=(x-1) (x+1)
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Answered by
2
Answer:
(0) square (-1)
0(-1)
0
p(-1)= (-1) square (-1)
1-1
0
p(2)= (2) square (-1)
4-1
3
Step-by-step explanation:
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Answered by
17
p (0)= (0-1)(0+1)
= -1×1
= -1
p (-1)=(-1-1)(-1+1)
= -2×0
=0
p (2)=(2-1)(2+1)
= 1×3
= 3
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