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Question no -: 35 any one u can answer
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Answer 1

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Answer 2

Solution :-

Let the speed of the goods train is x km/hr.

Then,

speed of express train=(x+20) km/hr.

Goods train leaves a station at 6pm and express train leaves the station at 8pm and express train reaches its destination 36min before goods train.

We known that,

→ Time taken = (Distance / speed)

Given ,

→ Total distance=1040km

→ Time taken by goods train to cover 1040 km = (1040)

→ Time taken by express train to cover 1040 km=1040/(x+20)

As per given condition we have Now,

→ 1040/x = 1040/(x+20) + 2(36/60)

→ 1040/x-1040/(x+20) = 2(3/5)

→ (1040x+20800-1040x)/(x²+20x) = 13/5

→ 13x²+260x = 104000

→ x² + 20x - 8000 = 0

Splitting The Middle Term now,

→ x²+100x-80x-8000 = 0

→ x(x+100)-80(x+100) = 0

→ (x-80)(x+100) = 0

Putting both Equal to Zero now,

x = 80km/h (or) x = (-100)km/h .

Here x>0 ,, Therefore x = 80 km/h.

Hence speed of goods train = 80 km/hr.

So, speed of express train = 100 km/hr.