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Circuit containing four identical resistors is provided.
We have to find current flow in the circuit
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◈ First of all, we need to find equivalent resistance of the circuit.
Let's solve it step by step.
1. Two resistors of 30Ω (ED and AC) are connected in parallel.
➝ 1/R = 1/30 + 1/30
➝ 1/R = 2/30
➝ R = 15Ω
2. Two resistors of 15Ω (BC) and R are connected in series.
➝ R' = 15 + R
➝ R' = 15 + 15
➝ R' = 30Ω
3. Two resistors of 15Ω and R' are connected in parallel.
➝ 1/Req = 1/15 + 1/R'
➝ 1/Req = 1/15 + 1/30
➝ 1/Req = 3/30
➝ Req = 10Ω
❅ As per ohm's law, current passing through a conductor is directly proportional to the applied potential difference. V ∝ I
⇒ V = I × Req
⇒ 3 = I × 10
⇒ I = 0.3 A ❂
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