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QUESTION:
If n(U) = 125, y is two times of x and z is 10 more than x. Then find the vaues of x, y and z
ANSWER:
x = 21.25
y = 42.5
z = 31.25
GIVEN:
y = 2x
z = x + 10
TO FIND:
The vaues of x, y and z.
FORMULA:
EXPLANATION:
n(X) = x + 4 + 3 + 6
n(Y) = y + 4 + 3 + 17
n(Z) = z + 6 + 3 + 17
n(X ⋂ Y) = 4 + 3
n( X ⋂ Z) = 6 + 3
n(Y ⋂ Z) = 17 + 3
n(X ⋂ Y ⋂ Z) = 3
Substitute these values in the equation
125 = x + 4 + 3 + 6 + y + 4 + 3 + 17 + z + 6 + 3 + 17 - (4 + 3) - (6 + 3) - (17 + 3) + 3
Substitute y = 2x and z = x + 10
125 = x + 13 + 2x + 24 + x + 10 + 26 - 7 - 9 - 20 + 3
125 = 4x + 76 - 36
125 = 4x + 40
125 - 40 = 4x
4x = 85
x = 21.25
y = 2x = 42.5
z = x + 10 = 31.25
:
n(U) = 125, y is two times of x and z is 10 more than x. Then find the vaues of x, y and z
ANSWER:
x = 21.25
y = 42.5
z = 31.25
GIVEN:
y = 2x
z = x + 10
TO FIND:
The vaues of x, y and z.
FORMULA:
EXPLANATION:
n(X) = x + 4 + 3 + 6
n(Y) = y + 4 + 3 + 17
n(Z) = z + 6 + 3 + 17
n(X ⋂ Y) = 4 + 3
n( X ⋂ Z) = 6 + 3
n(Y ⋂ Z) = 17 + 3
n(X ⋂ Y ⋂ Z) = 3
Substitute these values in the equation
125 = x + 4 + 3 + 6 + y + 4 + 3 + 17 + z + 6 + 3 + 17 - (4 + 3) - (6 + 3) - (17 + 3) + 3
Substitute y = 2x and z = x + 10
125 = x + 13 + 2x + 24 + x + 10 + 26 - 7 - 9 - 20 + 3
125 = 4x + 76 - 36
125 = 4x + 40
125 - 40 = 4x
4x = 85
x = 21.25
y = 2x = 42.5
z = x + 10 = 31.25
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