Question

don't use quadratic formula in my last question of maths
.
.
.
.
.​

Answer 1

Step-by-step explanation:

12x^2-6(a^2+b^2)+3a^2b^2=0

factorise

12x^2-6a^2x-6b^2x-3a^2b^2=0

6x(2x-a^2)-3b^2(2x-a^2)=0

(6x-3b^2)(2x-a^2)=0

6x-3b^2=0,2x^2-a^2=0

x=b^2/2,x=a^2/2

pls mark my ans as brainiest

Answer 2

Step-by-step explanation:

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀