Math, asked by ganiealtafqwe, 2 months ago

don't write wrong answer otherwise I'll report u​

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Answered by Sanju1534
4

Answer:

 {x}^{2}  + x - 2

  {x}^{2}  + (2 - 1)x - 2

 {x}^{2}  + 2x - x - 2

x(x + 2) - 1(x + 2)

(x + 2)(x - 1)

(x + 2) (x -1) = 0

=> (x + 2) = 0 and (x - 1) = 0

=> x = -2 and x = 1

Zeros of this polynomial is -2 and 1

Ans. -2 and 1

Hope it helps.

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