Question

Donald is thrice as old as Mohan and subbu is twice as old as Donald. If Donald's age is 1 year less than all the average age of all three then subbu's age in years is

Answer 1

Answer:

ugghhhh its 2 you fool

Step-by-step explanation:

Answer 2

Answer:

Required age of Subbu is 18 years.

Step-by-step explanation:

Given,Donald is thrice as old as Mohan.

Let age of Donald be x years.

So according to question,age of Mohan is $\frac{x}{3}$ years.

Again given,Subbu is twice as old as Donald.

So,age of Subbu is 2x years.

It is also given that Donald's age is 1 year less than all the average age of all three.

So, average age of all of them

$= \frac{x + \frac{x}{3} + 2x }{3} \\ = \frac{3x + x + 6x}{3 \times 3} \\ = \frac{10x}{9} \: years$

According to question,

$x + 1 = \frac{10x}{9} \\ 9x + 9 = 10x \\ 10x - 9x = 9 \\ x = 9$

So age of Donald is 9 years.

Age of Mohan is $\frac{9}{3} = 3 \: years$

and age of Subbu is

$(2 \times 9) = 18 \: years$

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