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3,-1,-1/3
p[x]=3x³-5x²-11x-3,where a=3,b= -5,c= -11,d= -3
first you have to put 3 in p{x} and you will get zero,like that you have to add -1and -1/3 in p[x] and you will get zero
remaining in your maths text
p[x]=3x³-5x²-11x-3,where a=3,b= -5,c= -11,d= -3
first you have to put 3 in p{x} and you will get zero,like that you have to add -1and -1/3 in p[x] and you will get zero
remaining in your maths text
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