Question

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The person applies F force horizontally on the smaller block as shown in figure. The coefficient of static
friction is mu between the blocks and the surface. Find the force exerted by the vertical wall on mass M.
What is the value of action-reaction forces between m and M?​

Answer 1

Answer:

The person applies F force horizontally on the smaller block as shown in figure. The coefficient of static

friction is u between the blocks and the surface.

Explanation:

Let N2  be the normal forces acting between (m and M)

Draw  FBD of this block.

For block m,

F – N2 – f = 0

For block M

N2 – N3 – f = 0

f = umg and uMg respectively.

Answer 2

Explanation:

The person falls F force