Math, asked by gunjjaan, 1 year ago

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a number is selected ramdomly from 10 to 100 find the probability of 
1.getting 2 digit number
2.getting a number multiple of 5
3.getting a 2 digit number in which sum of the 2 digit is 8

Answers

Answered by Anonymous
4
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(i) 90/91

(ii) 19/91

(iii) 8/91

Step-by-step explanation:

experiment: selecting a number randomly from 10 to 100.

no. of total possible outcomes = 91

(i) event : getting 2 digit number

no. of favourable outcomes = 90


P(E) = (no. of favourable outcomes for the event)/ (no. of total possible  outcomes).

=> P(E) = 90/91

________________
___________


(ii) event : getting a number multiple of 5

no. of favourable outcomes = 19

 P(E) =   (no. of favourable outcomes for the event)/(no. of total possible  outcomes).

=> P(E) = 19/91

_______________
__________


(iii) event : getting a 2 digit number in which sum of the 2 digit is 8

no. of favourable outcomes = 8

P(E) = (no. of favourable outcomes for the event)/(no. of total possible  outcomes).

P(E) = 8/91

________________________________________________
Answered by ssvijay738
0

experiment: selecting a number randomly from 10 to 100.

no. of total possible outcomes = 91

(i) event : getting 2 digit number

no. of favourable outcomes = 90

no. of favourable outcomes for the event

P(E) = ---------------------------------------------------------------

no. of total possible outcomes.

P(E) = 90/91

(ii) event : getting a number multiple of 5

no. of favourable outcomes = 19

no. of favourable outcomes for the event

P(E) = ---------------------------------------------------------------

no. of total possible outcomes.

P(E) = 19/91

(iii) event : getting a 2 digit number in which sum of the 2 digit is 8

no. of favourable outcomes = 8

no. of favourable outcomes for the event

P(E) = ---------------------------------------------------------------

no. of total possible outcomes.

P(E) = 8/91

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