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a number is selected ramdomly from 10 to 100 find the probability of
1.getting 2 digit number
2.getting a number multiple of 5
3.getting a 2 digit number in which sum of the 2 digit is 8
Answers
(i) 90/91
(ii) 19/91
(iii) 8/91
Step-by-step explanation:
experiment: selecting a number randomly from 10 to 100.
no. of total possible outcomes = 91
(i) event : getting 2 digit number
no. of favourable outcomes = 90
P(E) = (no. of favourable outcomes for the event)/ (no. of total possible outcomes).
=> P(E) = 90/91
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(ii) event : getting a number multiple of 5
no. of favourable outcomes = 19
P(E) = (no. of favourable outcomes for the event)/(no. of total possible outcomes).
=> P(E) = 19/91
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__________
(iii) event : getting a 2 digit number in which sum of the 2 digit is 8
no. of favourable outcomes = 8
P(E) = (no. of favourable outcomes for the event)/(no. of total possible outcomes).
P(E) = 8/91
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experiment: selecting a number randomly from 10 to 100.
no. of total possible outcomes = 91
(i) event : getting 2 digit number
no. of favourable outcomes = 90
no. of favourable outcomes for the event
P(E) = ---------------------------------------------------------------
no. of total possible outcomes.
P(E) = 90/91
(ii) event : getting a number multiple of 5
no. of favourable outcomes = 19
no. of favourable outcomes for the event
P(E) = ---------------------------------------------------------------
no. of total possible outcomes.
P(E) = 19/91
(iii) event : getting a 2 digit number in which sum of the 2 digit is 8
no. of favourable outcomes = 8
no. of favourable outcomes for the event
P(E) = ---------------------------------------------------------------
no. of total possible outcomes.
P(E) = 8/91