Question

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A constant force of 200 N acts upon a stationary object of mass 10 KG for 2 sec .What velocity does it generate ?

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Answer 1

Explanation:

F = ma

200 = 10 × a

a = 20 m/s^2

v = u +at

v = at

...(object was initially at rest).....

v = 20 × 2

v = 40 m/s

Answer 2

$\Large\bold{\underline{\underline{Answer:-}}}$

$\huge{40\:m/s}$

$\sf\small\bold{\underline{\underline{Step-By-Step\:Explanation:-}}}$

We know that

$\sf\Large\boxed{F =ma}$

Here Given F = 200 N, m = 10 kg

Substituting in the equation

$\sf\Large{200=10\times\:a}$

On solving

$\sf\Large{\Rightarrow\:a = 20 \:ms^{-2} }$

Now, It is said the body initially is rest therefore initial velocity (u) must be zero

u = 0

Applying Newton 1st Law of Motion :

$\sf\Large\boxed{v =u + at}$

Substituting the values to find final velocity at t= 2 sec

$\sf\bold{v = 0 + 20 \times \:2}$

$\bf\bold{\Rightarrow\:v = 40 \:m/s}$

Hence, the final velocity is 40 m/s