Question

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Answer 1

Answer:

angle APB is of 90°.

Step-by-step explanation:

hint-sum of adjacent angles of a llgm is 180°

so,angle B+angle C =180°

then angle B will be 80°

similarly, angle A will be 100°

now,

there is bisector of angle A and B so they

will be 50°and 40°.

now, in triangle APB

angle PAB +angle ABP +angle P =180°

so,after solving we will get that-

angle APB is of 90°.

please mark me as a brainliest.

Answer 2

Answer:

90°

The answer by allenite38 is not derived properly as it is not mentioned that the figure is a parallelogram

Step-by-step explanation:

In the quadrilateral ∠A+∠B+∠C+∠D=360°

=> ∠A+∠B+100+80=360°

=> ∠A+∠B=180°

Hence

$\frac{1}{2} (∠A+∠B+) = \frac{180}{2} = 90$

In ΔPAB

$\frac{1}{2} ∠A + \frac{1}{2}∠B +∠p = 180$

$∠p = 180 - 90 = 90$