Question

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Solveeeeee!!!​

Answer 1

Hello❤!!

❤Refer to given attachment ❤

Answer 2

$\huge\pink{\mid{\underline{\overline{\tt Answer :-}} \mid}}$

$\huge\mathfrak{ Solution :-}$

It can be observed that ΔBQC and parallelogram ABCD lie on the same base BC and these are between the same parallel lines AD and BC.

∴Area (ΔBQC) = 1/2 Area (ABCD) ... (1)

Similarly, ΔAPB and parallelogram ABCD lie on the same base AB and between the same parallel lines AB and DC.

∴ Area (ΔAPB) = 1/2 Area (ABCD) ... (2)

From equation (1) and (2), we obtain Area (ΔBQC) = Area (ΔAPB)