Math, asked by darshanaparida, 8 months ago


Doodheri lal, a milk seller has two types of milk. Type 1 contains 80% water and Type 2 contains 25% water. He buys 20 litres of Type 2 milk from the market and converts it
into Type 1 milk by adding water to it. If he then sells Type 1 milk at the same price at which he bought Type 2 milk, what is his total profit percentage? Assume water is
free of cost
Pick ONE option
A) 275%
B) 200%
C) 80%
D) 125%

Answers

Answered by amitnrw
2

Given :  Doodheri lal, a milk seller has two types of milk. Type 1 contains 80% water and Type 2 contains 25% water. He buys 20 litres of Type 2 milk from the market and converts it  into Type 1 milk by adding water to it.

Sells Type 1 milk at the same price at which he bought Type 2 milk,

To find :  total profit percentage

Solution:

Let say cost Price of Type 2  Milk =  Rs  C  per litre

Cost for 20 litre = Rs 20C

Type 2 contains 25% water.

=> Water = (25/100) 20  =  5 Litre

Let say he mix w litre water

Then mixture become = 20 + W litre

while water becomes = 5 + W litre

Type 1 contains 80% water

=>  100 * ( 5 + W)/ (20 + W)  = 80

=> 5 * ( 5 + W)/ (20 + W)  = 4

=> 25 + 5W = 80 + 4W

=> W = 55  

55 Litre water is added

so total becomes = 20 + 55 = 75 litre  

Selling Price = Rs 75C

Profit = 75C - 20C = Rs 55C

Profit % = (55C / 20C) * 100

= 55 * 5

= 275 %

option A is correct

total profit percentage = 275 %

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