Question

Doors of dam are 20m below the surface of water in the dam. If one door is opened what will

be the speed of the water that flows out of the door ? (g=9.8m/S2)​

Answer 1

Answer:

h=20m

from toricelli law

v=$\sqrt{2gh$

$\sqrt{2*9.8*20$

19.79 m/s

Explanation:

correct answer

Answer 2

Given:

Doors of dam are 20m below the surface of water in the dam.

To find:

Speed of water when one door is opened?

Calculation:

In this kind of questions, you need to apply TORRICELLI'S LAW:

• Let Velocity of Efflux be v_(e):

$\rm \therefore \: v_{e} = \sqrt{2gh}$

• 'g' is gravity , 'h' is depth of door.

$\rm \implies \: v_{e} = \sqrt{2 \times 10 \times 20}$

$\rm \implies \: v_{e} = \sqrt{400}$

$\rm \implies \: v_{e} = 20 \: m/s$

So, Velocity of Efflux of water from dam is 20 m/s.