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Find the value of each of the following polynomial for the indicate value of variable :
(1) p(x) = 4x² – 3x + 7 at x=1
(ii) q(Y) = 2y3 – 4y + Root 11 at y=1
(iii)r(t) = 4t4 +3t3 - +t2+6 at t=p, teR
(iv) s(z) = Z3 – 1 at z = 1
(v) p (x) = 3x² + 5x - 7 at x = 1
(vi) q (z) = 5z3- 4z + Root2 at Z = 2
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Answer:
Step-by-step explanation:
Given, q(y)=2y
2
−4y+
11
We need to find value of polynomial at y=1
Put the value y=1 in the given polynomial, we get
q(y)=2(1)
2
−4(1)+
11
⇒q(y)=2−4+
11
⇒q(y)=2−4+3.32
⇒q(y)=1.32
Therefore, q(y)=1.32
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